<PRE><B>Question 1031111</B>
x1		y1	x2	y2						
0		-2	6	0						
										
slope m =		(y2-y1)/(x2-x1)								
(	0	-	-2	)/(	6	-	0	)		
(	2	/	6	)  						
m=		 1/3						 		
The required line passes through both the points. So we select one point and plug it with the slope 										
Plug value of  the slope  and point			(	0	,	-2	) in			
Y	=	m	x	+	b					
-2.00	=	 1/3	*	0	+	b				
-2.00	=	0    	+	b						
b=	-2    	+	-0    							
b=	-2      									
So the equation  will be									
Y 	=	 1/3	x		-2    					
m.ananth@hotmail.ca										
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