Question 1031104
Prove that F(x) = 4x^3+x has no relative max or min without graphing. 
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F'(x) = 12x^2+1
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Solve: 12x^2+1 = 0
12x^2 = -1
x^2 = -1/12
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Solutions for that are not Real Numbers.
Therefore F(x) has no relative max or min.
Cheers,
Stan H.
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