Question 1030623
It cannot be {{{dy/dx=sqrt(y) - sqrt(x)}}}, because the slope field is defined for  negative values of x and y.

It cannot be {{{dy/dx= (2x)/y}}}, because the slopes in the 1st quadrant are negative (or the tangents are falling from left to right.)

It cannot be {{{dy/dx= x - y}}}, because this would make the slopes on the y-axis non-zero. (The slopes on the y-axis are 0.)

But the DE {{{dy/dx= - xy}}} would satisfy qualitatively all the conditions as illustrated in the slope field.