Question 1031032
Between 27 and 57.
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Chebyshev's Theorem says that {{{P(abs(X - mu) <= k*sigma)= P(abs(X - 42) <= 12k) >= 1-1/k^2}}} for any distribution with mean {{{mu}}} and standard deviation {{{sigma}}}.

To find k, let {{{1 - 1/k^2 = 0.36}}}

==> {{{0.64 = 1/k^2}}} ==> {{{k^2 = 1/0.64}}}  ==> k = 1.25.

==> {{{abs(X - 42) <= 12*1.25}}} ==> {{{abs(X - 42) <= 15}}}

==> {{{-15 <= X - 42 <= 15}}}  ==> {{{27 <= X <= 57}}}.