<PRE><B>Question 1031036</B>
he terminal side of an angle in standard position passes through the point (-1,5). Calculate the values of the six trigonometric functions for angle. 
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Notice:: The terminal point is in QII where x is negative and y is positive.
x = -1 ; y = 5 ; So, r = sqrt[1^2+5^2] = sqrt(26)
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sin = y/r = 5/sqrt(26)
cos = x/r = -1/sqrt(26)
tan = y/x = -1/5
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csc = 1/sin
sec = 1/cos
cot = 1/tan
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Cheers,
Stan H.
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