Question 1030993
First we divide by 2 and get
{{{ 2x^2 + 3x - 5 = 0 }}}
{{{ x^2 + (3/2)x - 5/2 = 0 }}}
Take half of the middle coefficient and square it, then add that to both sides and get
{{{x^2 + (3/2)x + 9/16 - 5/2 = 9/16}}}
{{{x^2 + (3/2)x + 9/16 = 49/16}}}
Choice B is closest, but the x needs to be in the numerator.