<PRE><B>Question 1030877</B>
Jesse flies a plane against a headwind for 3224 miles. The return trip with the wind took 10 hours less time. If the wind speed is 5 mph, how fast does Jesse fly the plane when there is no wind?

let speed of plane be x mph
wind speed = 5 mph

against wind time= 3224/(x-4)

with wind time = 3224/(x+4)



 3224/(x-4)- 3224/(x+4)=10

simplify

3224(x+4) - 3224(x-4) = 10(x+4)(x-4)

3224x +3224*4 -3224x +3224*4= 10x^2 -160

2*(3224(4)+160 =10x^2

solve for x

x= 50.9 mph  speed of plane in still air

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