Question 1030563
The two last statements are wrong.  You are trying to relate two factors, unknown ones, to 24.  What happens if you try to evaluate x+5=25 using x=24?


{{{(24)+5=24}}}
{{{29=24}}}
Very clearly false.


The goal would be solve for the variable, x.
{{{x(x+5)=24}}}, and you may expect two integers to give the product 24.
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{{{x(x+5)-24=0}}}
{{{x^2+5x-24=0}}}
Is this factorable?  If yes, THEN YOU COULD USE ZERO PRODUCT RULE.
{{{(x-3)(x+8)=0}}}
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Obviously the two possible solutions for x are  3  or  -8.