Question 1030525
y=3x^2
y=3x^2+bx+c
8=c, when x=0.
y=3x^2+8
The transformation is up 8 units.
y=3(x-0)^2+8 is the parabola written in vertex form.  y=3x^2 becomes congruent with the parabola made by transforming it 8 units upward or positive.  That is the answer.
{{{graph(300,200,-10,10,-10,30,3x^2,3x^2+8)}}}