Question 1030507
Given sin(theta)=-3/8, and (theta) is in quadrant III, find the exact value of the remaining 5 trigonometric functions.
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By definition sin(t) = y/r. 
In QIII, y = -3 and r = 8
Then x = -sqrt(8^2-3^2) = -sqrt(55)
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sin = -3/8
cos = x/r = -sqrt(55)/8
tan = y/x = 3/sqrt(55)
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csc = 1/sin
sec = 1/sec
cot = 1/tan
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Cheers,
Stan H.
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