Question 1030128
FOIL only work for factors with 2 terms.
You can use the distributive property (which FOIL is really in disguise).
{{{(4z^3+6z^2+9z+7)*(4z+1)=(4z^3+6z^2+9z+7)*(4z)+(4z^3+6z^2+9z+7)*(1)}}}
{{{(4z^3+6z^2+9z+7)*(4z+1)=(16z^4+24z^3+36z^2+28z)+(4z^3+6z^2+9z+7)}}}
{{{(4z^3+6z^2+9z+7)*(4z+1)=16z^4+(24z^3+4z^3)+(36z^2+6z^2)+(28z+9z)+7)}}}
{{{(4z^3+6z^2+9z+7)*(4z+1)=16z^4+28z^3+42z^2+37z+7)}}}