Question 1030279
A target in archery competition measures 122 centimeters in diameter.
 A contestant's first arrow lands 50 cm to the left and 30 cm above the center of the bulls-eye.
 Did the arrow hit the target?
:
The distance from center of the target to edge will be the radius; 122/2 = 61 cm
:
The distance the arrow is from the center of the target is the hypotenuse of a right triangle formed by the two given sides, 50 and 30
h = {{{sqrt(50^2+30^2)}}}
h = 58.31 cm
:
The arrow will indeed pierce the target