Question 1030352
Use Cramer's rule,
{{{A=(matrix(3,3,
2,-3,1,
3,2,-1,
5,-2,1))}}}
{{{abs(A)=8}}}
,
,
,
{{{A[x]=(matrix(3,3,
0,-3,1,
3,2,-1,
1,-2,1))}}}
{{{abs(A[x])=4}}}
,
,
,
{{{A[y]=(matrix(3,3,
2,0,1,
3,3,-1,
5,1,1))}}}
{{{abs(A[y])=-4}}}
,
,
,
{{{A[z]=(matrix(3,3,
2,-3,0,
3,2,3,
5,-2,1))}}}
{{{abs(A[z])=-20}}}
,
,
,
{{{x=abs(A[x])/abs(A)=4/8=1/2}}}
.
.
{{{y=abs(A[y])/abs(A)=-4/8=-1/2}}}
.
.
{{{z=abs(A[z])/abs(A)=-20/8=-5/2}}}
.
.