Question 88789
Sketch the graph of the hyperbola y^2/25- x^2/4= 1. Draw the fundamental rectangle. Find the equations of the asymptotes and label the asymptotes on your graph
STD. EQN IS 
(Y-K)^2/B^2 - (X-H)^2/A^2 =1 
COMPARING H=K=0....A=2......B=5
CENTER IS (H,K)=(0,0)
TRANSVERSE AXIS IS X=H=0
LENGTH OF TRANSVERSE AXIS = 2B=10
CONJUGATE AXIS IS Y=K=0
LENGTH OF CONJUGATE AXIS = 2A =4
VERTICES ARE [H,K+-B]=(0,5) AND (0,5)
USE THIS DATA TO SKETCH.IF NECESSARY GIVE SOME VALUES TO X AND FIND Y AND PLOT
CURVES ARE SYMMETRIC ABOUT AXES 
ASYMPTOTES ARE GIVEN BY 
Y^2/25 - X^/4 = 0 
[(Y/5)+(X/4)][(Y/5)-(X/4)]=0
Y/5 = X/4
AND Y/5 = -X/4
GRAPH IS SHOWN BELOW
{{{ graph( 500, 500, -10, 10, -10, 10, 1.25*x, -1.25x,2.5*(x^2+4)^0.5,-2.5*(x^2+4)^0.5) }}}