Question 1030340
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Solve the equation. Write any complex solutions in standard form for a complex number. (Enter your answers as a comma-separated list.)

8x^3+4x^2-26x=0
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Factor left side

{{{2x*(4x^2 + 2x - 13)}}} = {{{0}}}.

One root is x = 0.
To find other roots, you need solve this quadratic equation

{{{4x^2 + 2x - 13}}} = {{{0}}}.

Use quadratic formula. The two other roots are 

{{{x[1,2]}}} = {{{(-1 +- sqrt(53))/2}}}.
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