Question 1030369
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-sin(pi/2-x) = sqrt(3)*sin(x)

(0 <= x < pi)
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1.  {{{-sin(pi/2-x)}}} = {{{-cos(x)}}}.



2.  Therefore, the original equation takes the form

    {{{-cos(x)}}} = {{{sqrt(3)*sin(x)}}}.



3.  Then  {{{sin(x)/cos(x)}}} = {{{-1/sqrt(3)}}},   or

    {{{tan(x)}}} = {{{-sqrt(3)/3}}}.

    x = {{{5pi/6}}},  or  150°.
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