Question 88748

  I'm suppose to comple the square
x^2-6x+
 

   Bring it to the standard form i.e, x^2-2xy+y^2
                                      x^2-2.x(3)+()^2
                                      x^2-2.x.(3)+()^2  when compared with the standard  form  we find in place of y = 3   
   BY adding (3)^2   the square is completed
                Therefore the given expression becomes x^2-6x+9 = (x-3)^2.