Question 1030185
In a lottery game, a player picks six numbers from 1 to 24. If the player matches all six numbers, they win $ 20,000. Otherwise, they lose $1. Assume it costs nothing to play. 
What is the expected value of this game? 
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Random "winning" numbers::....... 20,000.........-1
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Corresponding probabilities:: ....1/24C6........1 - 1/(24C6)
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Expected value = 20,000*(1/24C6) - 1/[1-(1/24C6)]
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= 20000/134596 - 1/(1 - 7.43*10-6)
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= 0.1486-0.9999
= -$0.85  = -85 cents
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Cheers,
Stan H.
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