Question 1030122
Let {{{ a }}} = the cost of a can of baked beans
Let {{{ b }}} = the cost of a packet of sugar
Let {{{ c }}} = the cost of a packet of biscuits
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(1) {{{ 5a + 4b + 2c = 150 - 26 }}}
(2) {{{ a = (1/2)*c }}}
(3) {{{ b = c - 3 }}}
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There are 3 equations and 3 unknowns, so it's solvable
Substitute (2) and (3) into (1)
(1) {{{ 5*( (1/2)*c ) + 4*( c-3 ) + 2c = 150 - 26 }}}
(1) {{{ (5/2)*c + 4c - 12 + 2c = 124 }}}
(1) {{{ ( 5/2 )*c + 6c = 136 }}}
(1) {{{ ( 5/2 )*c + ( 12/2 )*c = 136 }}}
(1) {{{ (17/2)*c = 136 }}}
(1) {{{ 17c = 272 }}}
(1) {{{ c = 16 }}}
and
(2) {{{ a = (1/2)*16 }}}
(2) {{{ a = 8 }}}
and
(3) {{{ b = 16 - 3 }}}
(3) {{{ b = 13 }}}
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R8.00 = the cost of a can of baked beans
R13.00 = the cost of a packet of sugar
R16.00 = the cost of a packet of biscuits
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check:
(1) {{{ 5a + 4b + 2c = 150 - 26 }}}
(1) {{{ 5*8 + 4*13 + 2*16 = 150 - 26 }}}
(1) {{{ 40 + 52 + 32 = 124 }}}
(1) {{{ 124 = 124 }}}
OK