Question 1029984
tan^2 theta/ (sec^2 theta-1)^2 =1+cos theta/1- cos theta 



{{{tan^2 (theta)/ (sec^2(theta)-1)^2 }}}



{{{(sec^2 (theta)-1)/ (sec^2(theta)-1)^2 }}}



{{{ (sec(theta)+1)(sec(theta)-1)/(sec^2(theta)-1)^2 }}}


{{{ (sec(theta)+1)/(sec(theta)-1) }}}



{{{(1/(cos(theta)+1))/(1/(cos(theta)-1))}}}



{{{(((cos(theta)+1))/cos(theta))/((1-cos(theta))/(cos(theta)))}}}


{{{(1+cos(theta))/(1-cos(theta))}}}