<PRE><B>Question 1030009</B>
What is the length of the base of an isosceles triangle if the congruent sides are 2.5m and the vertex angle is 25 degrees 
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Law of Cosines::
B^2 = 2.5^2 + 2.5^2 - 2*2.5^2*cos(25)
B^2 = (2.5^2)(1-cos(25))
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B^2 = 0.5856
Base = 0.7652 m
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Cheers,
Stan H.</PRE>