Question 1029980
Use Cramer's rule,
{{{A=(matrix(3,3,
1,-1,0,
2,0,-3,
0,2,1))}}}
{{{abs(A)=8}}}
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.
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{{{A[x]=(matrix(3,3,
6,-1,0,
16,0,-3,
4,2,1))}}}
{{{abs(A[x])=64}}}
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.
.
{{{A[y]=(matrix(3,3,
1,6,0,
2,16,-3,
0,4,1))}}}
{{{abs(A[y])=16}}}
.
.
.
{{{A[z]=(matrix(3,3,
1,-1,6,
2,0,16,
0,2,4))}}}
{{{abs(A[z])=0}}}
.
.
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{{{x=abs(A[x])/abs(A)=64/8=8}}}
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{{{y=abs(A[y])/abs(A)=16/8=2}}}
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{{{z=abs(A[z])/abs(A)=0/8=0}}}
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