Question 1029999
<pre>
Let the smaller digit = x
Then since the digits are consecutive,
the larger is 1 more than the smaller digit,
So the larger digit = x+1
</pre>
if the digits are interchanged. the original value is increased...
<pre>
That tells us that the original number is smaller than the
number with the digits interchanged.  So the original number
has the smaller first (or tens) digit.  Therefore:
<pre>
The original number = 10x + (x+1)

The number with the digits reversed = 10(x+1) + x
</pre>
if the digits are interchanged. the original value is increased by 9
<pre>
10(x+1) + x = 10x + (x+1)

Solve that for x and what you get for x will be the smaller digit,
then add 1 to it and what you get will be the larger digit.  You
finish.

Edwin</pre>