Question 1029970
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos 2u\ =\ 1\ -\ 2\sin^2u]


Just do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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