Question 1029973
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos\varphi\ =\ \frac{1}{\sec\varphi}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\varphi\ =\ \pm\sqrt{1\ -\ \cos^2\varphi}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan\varphi\ =\ \frac{\sin\varphi}{\cos\varphi}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cot\varphi\ =\ \frac{1}{\tan\varphi}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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