Question 1029979
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The vertical height (in feet) of any projectile is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ v_ot\ +\ h_o]


Where *[tex \Large v_o] is the initial vertical component of the velocity (positive = up, negative = down) and *[tex \Large h_o] is initial height.  Initial means the value of the parameter at time *[tex \Large t\ =\ 0]


Evaluate your function at zero, that is *[tex \Large h(0)\ =\ ]?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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