Question 1029905
From the distance formula, {{{(x-2)^2 + (y-7)^2 = 13^2}}}

{{{(2y + 8)^2 + (y-7)^2 = 169}}}, after substituting x = 2y + 10 into the equation above.

<==>  {{{5y^2 + 18y +113 = 169}}} after simplifying.

==>  {{{5y^2 + 18y -56 =0}}} ==> (5y+28)(y-2) = 0 ==> y = -28/5, 2

==> x = -6/5, 14.

Therefore the points are (-6/5, -28/5); (14,2).