Question 1029943
{{{f(x) = (x-(3+2i))(x - (3-2i))(x+1)(x-2) =  ((x-3)-2i)((x - 3)+2i)(x+1)(x-2) = ((x-3)^2+4)(x^2-x-2)}}}

={{{(x^2-6x +13)(x^2-x-2)}}}.  (Just do the necessary expansion.)

(Note: Any polynomial of the form {{{k(x^2-6x +13)(x^2-x-2)}}} where k is any non-zero real number, will do just fine.)