Question 1029777
{{{(3y-1)(2y+k) = 6y^2 -2y + 3ky -k =  6y^2 + (3k-2)y -k}}}

==> a = 6, b = 3k-2, and -5 = -k ==> k = 5.

==> a + b = 6 + 3*5-2 = 6 + 15 - 2 = 19.