<PRE><B>Question 1029574</B>
10 cos &amp;#952; + 13 tan &amp;#952; = sec &amp;#952; 
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10cos + 13(sin/cos) = 1/cos
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10cos^2 + 13sin = 1
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10(1-sin^2) + 13sin = 1
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10 - 10sin^2 + 13sin = 1
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10sin^2 - 13sin -9 = 0
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(2sin+1)(5sin-9) = 0
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Only acceptable solution::
sin(t) = -1/2
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Ans:: t = (7/6)pi or t = (11/6)pi
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Cheers,
Stan H.
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