Question 88688
THEY MEET AFTER THREE HOURS FROM THE START & EACH TRAVEL FOR 3 HOURS. ONE TRAXELS @ X MPH & THE OTHER @ (X+10) MPH.
240=3X+3(X+10)
240=3X+3X+30
6X=240-30
6X=210
X=210/6
X=35 MPH FOR THE SLOWER CAR.
35+10=45 MPH FOR THE FASTER CAR.
PROOF
240=3*35+3*45
240=105+135
240=240