Question 1029521
how to solve the following equation using only log of 10 or natural log:
12500=8400(1+r)^8
----------
(1+r)^8 = 125/84
{{{1 + r = root(8,(125/84))}}}
{{{r = root(8,(125/84)) - 1}}}
r =~ 0.05094222
=~ 5.09%
=============
No logs needed.