Question 1029450
2x² + 8x +7 = 0
The quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
In this equation a=2; b=8; c=7
{{{x = (-8 +- sqrt(8^2-4*2*7 ))/(2*2) }}}
{{{x = (-8 +- sqrt(64-56))/4 }}}
{{{x = (-8 +- sqrt(8))/4 }}}
Two solutions
x = {{{(-8 + 2.828)/4}}}
x = -1.2929
and
x = {{{(-8 - 2.828)/4}}}
x = -2.707
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You can check your solutions in the original equation, replacing x and see if the results are 0 or very close to it since we have decimal solutions