Question 1028021
(a)  λ = {{{(1.2/3)*11 = 4.4}}}

(b)  Poisson pmf:  {{{p(x) = ((lambda)^x/(x!))*e^(-lambda)}}}

==> {{{p(X >=1) = 1-p(X=0) = 1-((4.4)^0/(0!))*e^(-4.4) = 0.9877}}}

(c)  {{{p(X=3) = 1-p(X = 0) - p(X=1) - p(X=2) = 1-(4.4^0/(0!)+ 4.4^1/(1!) + 4.4^2/(2!))*e^(-4.4) = 0.8149}}}

(d)  {{{p(X=0) = e^(-4.4)= 0.0123}}}