Question 1029332
{{{log((5^(1-x)))=log((2^x))}}}


{{{(1-x)*log((5))=x*log((2))}}}


{{{log((5))-x*log((5))=x*log((2))}}}


{{{x*log((2))+x*log((5))=log((5))}}}


{{{x(log((2))+log((5)))=log((5))}}}


{{{highlight(x=log((5))/(log((2))+log((5))))}}}
Decide what base you want and go from there.