Question 1029331
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log x = log 12- log (x+1)
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<pre>
log(x) = log(12)- log (x+1)  --->

log(x) + log(x+1) = log(12)  --->

log(x*(x+1)) = log(12)  --->

x*(x+1) = 12  --->

{{{x^2 + x - 12}}} = {{{0}}}  --->

Factor left side

(x+4)*(x-3) = 0,

The roots of this equation are  x = -4,  and/or  x = 3.

Only  x = 3  fits due to logarithm.

<U>Answer</U>.  x = 3.
</pre>