Question 1029273
Hi I'm trying to integrate the following equation:

(5sin2θ +2cos4θ)dθ 

my answer is ((-5cos2θ)/2) + 1/2 sin4θ +c but I am unsure if this is the correct answer. Can anyone please check and if necessary point me in the right direction . Cheers
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Differentiate your result:
(d/dt)(-5cos(2t)/2 + sin(4t)/2 + C)
= 5sin(2t) + 2sin(4t)
Looks right.