<PRE><B>Question 1029267</B>
 If the quadratic 3x^2+bx+10 can be written in the form a(x+m)^2+n, where m and n are integers, what is the largest integer that must be a divisor of b? 
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3x^2 + bx.....+10
3(x^2 + (b/3)x + (b/6)^2) + [10 - 3(b/6)^2]
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n must be a integer:
So, 10-(3(b^2/36)) = 10-(b^2/12)
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 b^2 must be a multiple of 12
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 etc.
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Cheers,
Stan H.
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