Question 1029191
suppose k = 1, then we have
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y = x^3 + x^2 -8x -12
:
the graph of this function is
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{{{ graph( 300, 200, -4.5, 3.8, -40, 30, x^3 + x^2 -8x -12) }}}
:
x^3 + x^2 -8x -12 = (x-3) * (x+2)^2
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note that (-2,0) and (3,0) define the zeros for the function, k can be any constant since k * 0 = 0
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