Question 1029260
Perpendicular lines have slope that are negative recpirocals. 
Paralllel lines have slopes that are identical.
{{{y=x-6}}}
{{{m[p]*(1)=-1}}}
{{{m[p]=-1}}}
So then using the point slope form,
{{{y-2=-1(x-(-1))}}}
{{{y-2=-(x+1)}}}
{{{y-2=-x-1}}}
{{{highlight(y=-x+1)}}}
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2. DO it the same way as #1.
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3. {{{m[p]=3}}}
{{{y-10=3(x-4)}}}
{{{y-10=3x-12}}}
{{{highlight(y=3x-2)}}}