Question 1028929
Convert to vertex form,
{{{y=2(x^2-2x)-1}}}
{{{y=2(x^2-2x+1)-1-2}}}
{{{y=2(x-1)^2-3}}}
Vertex is at (1,-3) and the parabola opens upwards.
So the domain is all real numbers.
The range is [{{{-3}}},{{{infinity}}}).