Question 88616
Equation of the given line is y = (2/3)x + 1
==> slope of this line =2/3
The required line is parallel to this line.

So slope of the required line = 2/3 [parallel lines have the same slope]

It passes through (0,-3)

So the equation is y-y1 = m(x-x1)

==>             (y - (-3)) = (2/3)(x-0)

==>                y+3 = (2/3)x

==>                y = (2/3)x - 3 is the equation of the required line L