Question 1029166
let x = the age of the son.
let y = the age of the father.


the age of the son and the father are in the ratio of 3/10.
this means that x/y = 3/10.


the father is 56 years older than the son.
this means that y = x + 56.


in the equation of x/y = 3/10, replace y with x + 56 to get:
x/(x+56) = 3/10.


cross multiply to get 10x = 3*(x+56).
simplify to get 10x = 3x + 168.
subtract 3x from both sides of the equation to get 7x = 168.
divide both sides of the equation by 7 to get x = 24.


the age of the son is 24.
the age of the father is 24 + 56 = 80.
the ratio of the son's age to the father's age is 24/80 = 3/10.


solution looks good.
age of the son is 24.
age of the father is 80.