Question 1029154
Hi, Can anyone solve this problem? The sum of three numbers is 9. The first minus the second, plus the third is 3. The first minus the third is 1 more than the second.  What are the numbers?
<pre>Let the 1<sup>st</sup>, 2<sup>nd</sup>, and 3<sup>rd</sup>, be F, S, and T, respectively
Then we get the following:
                F + S + T = 9 ------ eq (i)
                F – S + T = 3 ------ eq (ii)
F – T = S + 1___F – S – T = 1 ------ eq (iii)
                       2T = 2 ------ Subtracting eq (iii) from eq (ii) 
T, or 3<sup>rd</sup> number = {{{2/2}}}, or {{{highlight_green(1)}}}

2F = 10 ---------- Adding eqs (iii) & (i)
F, or 1<sup>st</sup> number = {{{10/2}}}, or {{{highlight_green(5)}}}

5 + S + 1 = 9 ------- Substituting 1 for T, and 5 for F in eq (i)
6 + S = 9
S, or 2<sup>nd</sup> number = 9 – 6, or {{{highlight_green(3)}}}