Question 1029145
1011101010101
group this in groups of 3 starting 
at the right side 
1 011 101 010 101
Use place multipliers for
each of the groups of 3
[ 2^2 , 2^1 , 2^0 ]
1 3 5 2 5
This is the value in base 8 ( octal )
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Prove it with easy example:
1000100
1 0 4 in octal
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1*2^6 + 1*2^2 = 64 + 4 
64+ 4 = 68
and
1*8^2 + 4 = 64 + 4 
64 + 4 = 68
OK