Question 1029138
Part (A)


secant = 1/cosine so this means that if sec(theta) < 0, then cos(theta) < 0


Cosine is negative in quadrants II and III where the x coordinate of an ordered pair point is negative (eg: (-2, 5))


So sec(theta) < 0 only happens in Q2 or Q3


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Part (B)


You wrote "tan(theta) 0" but you forgot to put a symbol between the "tan(theta)" and the "0". So I have no idea if it's < or >. There isn't enough info to answer this problem.


IF it's tan(theta) > 0 then the answer would be Q1 and Q3 (since sine&cosine are both either together positive or together negative)
IF it's tan(theta) < 0 then the answer would be Q2 and Q4 (sine&cosine have different signs. One is positive, the other is negative)