Question 1029129
y=-x+4.  That gives a negative slope in the first quadrant' make y=-x+6,.  Those two lines have no solution. They are parallel.  The slope is the value in front of the x, and the y-intercept is the number at the end, the b in y=mx +b.  
Now say 2y=-2x+12.  That is the same as y=-x+6.  That line can have those two labels, and it has infinite solutions.  Extend these lines into the second quadrant, so you have a line with non-infinite  or non-zero slope in both quadrants.
x=-2.  That gives an undefined slope in the second quadrant.
y=-3  That gives a slope of 0 in the third quadrant.
y=x-4.  That gives a positive slope in the fourth quadrant.  Extend that line into the third quadrant so that you can say you have a line with that slope in the third quadrant.  
The -x+4 and x-4 will intersect.  
y=-x+6
y=x-4
2y=2, y=1.  When y=1, x=5.  So the lines intersect at (5,1).
I can't draw in here x=-2, but it is vertical along the x=-2 line.
Those fulfill the basic requirements for the quadrants. 
Those lines may be extended or not.
To make the shape with 6 more lines, you need one more vertical line, and you can put it anywhere.  The equation is x= whatever it is on the x-axis.
For the horizontal line, you may put it anywhere, and its equation is y- whatever it is.  
 
{{{graph(300,200,-10,10,-10,10,-x+2,-3,-x+6,x-4)}}}
This graph needs more lines to make 10.  You can draw any shape you want and erase the parts of the lines that are going to infinity.  For each line, where it crosses the y-axis is the intercept or b.  The slope of the line is positive if it goes up and to the right, and it is the change in y divided by the change in x.  This is one of those instances where it would be easier to draw the line on graph paper and figure out the equation from the intercept and the slope.  
For any two points, you can determine the slope:  change in y/change in x.
(2,3) and (4,9), the change in y is 9-3 or 6 divided by the change in x, which is 4-2 or 2. The slope is 3.
To get the equation of the line, use the point slope formula with slope 3.
y-3=3(x-2) using the first point.  y-3=3x-6; y=3x-3. This line crosses the y-axis at -3 and has a slope of 3, going up 3 for every 1 it goes to the right.
using the other point gives you the same answer.
y-9=3(x-4)
y-9=3x-12
y=3x-3.
See if that is enough to put in other lines and give their equation.  I'm not sure I understand the whole question, but this to me seems to fulfill the basic parts of it.