Question 1029068
.
Given that
log8 5 = 0.7740
and
log8 11 = 1.1531
evaluate the expression
log8 320
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<pre>
320 = 5*64 = {{{5*8^2}}}

Therefore,  {{{log(8, (320))}}} = {{{log(8, (5*8^2)))}}} = {{{log(8,(5)) + 2}}} = 0.7740 + 2 = 2.7740.

The info on {{{log(8,(11))}}} is excessive and is not used in this evaluation.
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