Question 1028882


There are 2 times when the ball's height is 5 ft. 
 On the way up and on the way down. 
 So if we plug in 5 for h, we should get 2 values for t 
 5 = 3 +26t -16t^2 

16t^2-26t+2=0

Find the roots of the equation by quadratic formula							
							
a=	16	b=	-26	c=	2		
							
b^2-4ac=	676	-	128				
b^2-4ac=	548			{{{sqrt(	548	)}}}=	23.41
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	26	+	23.41	)/	32		
x1=	1.54						
x2=(	26	-23.41	) /	32			
x2=	0.08						


t= 0.08 OR 1.54