Question 1028877
Let the numbers be a/r, a,ar


a/r + a +r =19

a/r*a*ar=219

a^3= 216

a=6

a+ar+ar^2 = 19r


6+6r+6r^2=19r

6r^2-13r+6 =0

6r^2-9r-4r+6=0

3r(2r-3)-2(2r-3)=0

(2r-3)(3r-2)=0

r=3/2 OR r=2/3

plug a & r 

when r=3/2

a/r = 6/(3/2) =4

a=6

ar = 9

4,6,9

OR r=2/3

a/r = 6/(2/3) =9

a= 6

ar = 4

9,6,4